再来一题! 给出年、月、日，计算该日是该年的第几天
给出年、月、日，计算该日是该年的第几天。[用函数]都是用C语言!!
改了一下标题:把再来一题!改为: 再来一题! 给出年、月、日，计算该日是该年的第几天
by hjack版主
[ 本帖最后由 hjack 于 2006-4-14 23:17 编辑 ]
#include <stdio.h>
int getnumber(int y, int m, int d){
int temp=0;
int i;
int a={31,28,31,30,31,30,31,31,30,31,30,31};
for(i=0;i<m;i++) temp+=a;
if(((y%4==0)&&((y%100!=0)||(y%400==0)))&&m>2)
temp++;
temp-=(a-d);
return temp;
}
main(){
int y,m,d;
printf("Enter date:");
scanf("%d %d %d",&y,&m,&d);
printf("The number of the date is: %d.\n",getnumber(y,m,d));
}
output:
Enter date:1995 12 31
The number of the date is 365.
output:
Enter date:1996 12 31
The number of the date is 366.
output:
Enter date:2000 12 31
The number of the date is 366.
output:
Enter date:2100 12 31
The number of the date is 365.
[ 本帖最后由 黯然销魂 于 2006-4-15 16:17 编辑 ] main()
{
int day,month,year,sum,leap;
printf("\nplease input year,month,day\n");
scanf("%d,%d,%d",&year,&month,&day);
switch(month)
{
case 1:sum=0;break;
case 2:sum=31;break;
case 3:sum=59;break;
case 4:sum=90;break;
case 5:sum=120;break;
case 6:sum=151;break;
case 7:sum=181;break;
case 8:sum=212;break;
case 9:sum=243;break;
case 10:sum=273;break;
case 11:sum=304;break;
case 12:sum=334;break;
default:printf("data error");break;
}
sum=sum+day;
if(year%400==0||(year%4==0&&year%100!=0))
leap=1;
else
leap=0;
if(leap==1&&month>2)
sum++;
printf("It is the %dth day.",sum);
getch();
}
C语言的
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