我得出答案系统还说我错，什么回事？

Ja5oN

这是我在北大OJ里的一道题目
我用我的代码能得出真确的答案
系统却说我错，怎么回事？
题目：

Description
Larry graduated this year and finally has a job. He's making a lot of money, but somehow never seems to have enough. Larry has decided that he needs to grab hold of his financial portfolio and solve his financing problems. The first step is to figure out what's been going on with his money. Larry has his bank account statements and wants to see how much money he has. Help Larry by writing a program to take his closing balance from each of the past twelve months and calculate his average account balance.
Input
The input will be twelve lines. Each line will contain the closing balance of his bank account for a particular month. Each number will be positive and displayed to the penny. No dollar sign will be included.
Output
The output will be a single number, the average (mean) of the closing balances for the twelve months. It will be rounded to the nearest penny, preceded immediately by a dollar sign, and followed by the end-of-line. There will be no other spaces or characters in the output.
Sample Input
100.00
489.12
12454.12
1234.10
823.05
109.20
5.27
1542.25
839.18
83.99
1295.01
1.75
Sample Output
$1581.42

代码：

#include<stdio.h>
void main()
{
float cbm[12];
int i;
float sum=0;
float ave;
float *p=cbm;
for(i=1;i<=12;i++)
{
  scanf("%f",p);
  p++;
}
p=cbm;
for(i=1;i<=12;i++)
{
  sum+=*p;
  p++;
}
ave=sum/12;
printf("%6.2f",ave);
}

补上链接http://acm.pku.edu.cn/JudgeOnline/problem?id=1004

[ 本帖最后由 Ja5oN 于 2007-3-12 13:48 编辑 ]

iptton

是格式问题吧..

iptton

建议下次最好把题目链接也帖出来

骑喱怪

输出格式不对吧,多一个少一个字符都不行.
$号呢,
还有系统给的测试用例数值可能很大

iptton

#include<stdio.h>
int main()
{
float a=0,b;
int i=0;
while(i++<12){
   scanf("%f",&b);
   a+=b/12;
}
printf("$%6.2f",a);
return 0;
}

Ja5oN

忘了“$”，又犯这种错误
不好意思

小I

topCoder 上的题目

Problem Statement
&nbsp;&nbsp;&nbsp;&nbsp;
A Fountain of Life is a special fountain that produces the elixir of life at a constant speed of elixir liters per second. A dark mage managed to cast a Curse of Death on the Fountain so in addition to the elixir it now produces a deadly poison at a constant speed of poison liters per second. Both the poison and elixir are collected in an infinitely large pool around the Fountain and form a mixture. The mixture will become deadly once the percentage of poison in the mixture is at least 50%. Your task is to calculate the time at which the mixture will become deadly. At the beginning (0-th second) the pool contains pool liters of 100% elixir.  Your program must return a double, the time in seconds at which the mixture becomes deadly. If the mixture never becomes deadly, return -1.0.
Definition
&nbsp;&nbsp;&nbsp;&nbsp;
Class:
FountainOfLife
Method:
elixirOfDeath
Parameters:
int, int, int
Returns:
double
Method signature:
double elixirOfDeath(int elixir, int poison, int pool)
(be sure your method is public)
&nbsp;&nbsp;&nbsp;&nbsp;

Notes
-
The returned value must be accurate to within a relative or absolute value of 1E-9.
Constraints
-
elixir will be between 1 and 10000, inclusive.
-
poison will be between 1 and 10000, inclusive.
-
pool will be between 1 and 10000, inclusive.
Examples
0)

&nbsp;&nbsp;&nbsp;&nbsp;
1
2
2
Returns: 2.0
At t = 0s there are 2 liters of 100% elixir. At t = 1s there are 3 liters of elixir and 2 liters of poison for a total volume of 5 liters. 2 liters of poison is 40% of 5 liters so the mixture is still not deadly. At t = 2s there are 4 liters of elixir and 4 liters of poison for a total volume of 8 liters. 4 liters of poison is exactly 50% of the mixture so it is now deadly.
1)

&nbsp;&nbsp;&nbsp;&nbsp;
200
100
1
Returns: -1.0
With 200 liters of elixir per second and only 100 liters of poison per second, the mixture never becomes deadly.
2)

&nbsp;&nbsp;&nbsp;&nbsp;
9999
10000
10000
Returns: 10000.0
It might take a long time for the mixture to become deadly.
3)

&nbsp;&nbsp;&nbsp;&nbsp;
1
10000
1
Returns: 1.0001000100010001E-4
On the other hand, it might take a short time for the mixture to become deadly.
4)

&nbsp;&nbsp;&nbsp;&nbsp;
40
43
41
Returns: 13.666666666666666

This problem statement is the exclusive and proprietary property of TopCoder, Inc. Any unauthorized use or reproduction of this information without the prior written consent of TopCoder, Inc. is strictly prohibited. (c)2003, TopCoder, Inc. All rights reserved.